- #1

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I'm supposed to find the second derivate of

[tex]f(x) = \frac{2-3x}{x^2}[/tex]

I started out with this:

[tex]f'(x) = \frac{-3}{x^2} + \frac{2-3x}{2x}[/tex]

[tex]f''(x) = \frac{3}{2x} + \frac{2-3x}{2}[/tex]

But it didn't take long until I found I was just making gibberish...

Any ideas?